Long long ago, in a village there used to be held an annual animal fair where only elephants, horses and sheep used to be sold. During one year the price-list in the fair was as follows:-
One Elephant --- $5
One Horse --- $1
Twenty Sheep --- $1
A merchant sent his servant with $100 to the fair and instructed him to buy 100 animals with the money....but the condition was that there had to be at least one animal of each kind in the lot and there must be no money left over.
How did the servant go about carrying out his task ?
The Last Legion 2007 Svenskt Tal Online
8 years ago
3 comments:
If the servant was smart, he bought 1 elephant, 19 horses, and 80 sheep. That's a total of 100 animals purchased for $28 with $72 change. Then the servant pocketed the leftover as his fee for having to herd that many animals back to his master's house.
That's not what you were looking for, was it?
Good try, this is what the answer is supposed to be:
The servant bought 19 elephants, 1 horse and 80 sheep.
Total number of animals = 19 + 1 + 80
= 100
Total cost = (19 x 5)+(1x1)+(80 x 1/20)
= 95 + 1 + 4
= 100
I like Jordan's answer better.
She would have even been right if she had switched the elephant and horses.
Hers was more creative.
The right answer?...yeah, um, that's what I had.
-Della
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